the product of 2 consecutive positive integer is 420. the integer
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Answered by
11
Let the one integer be x
second ineteger be x + 1
ATQ
x ( x + 1) = 420
x^2 + x = 420
x^2 + x - 420 = 0
x^2 + (21 - 20)x - 420 = 0
x^2 +21x - 20x - 420 = 0
x ( x + 21) - 20 ( x + 21) = 0
(x + 21) ( x - 20) = 0
The two numbers are positive so the integers are 20 and 21
second ineteger be x + 1
ATQ
x ( x + 1) = 420
x^2 + x = 420
x^2 + x - 420 = 0
x^2 + (21 - 20)x - 420 = 0
x^2 +21x - 20x - 420 = 0
x ( x + 21) - 20 ( x + 21) = 0
(x + 21) ( x - 20) = 0
The two numbers are positive so the integers are 20 and 21
maliksuvansh20p9lc0s:
thank u
Answered by
3
Let take the integer as ‘’a’’ and its consecutive is ‘’a + 1’’
Formula: a * (a + 1) = a + a2
a * (a + 1) = a + a2 = 420
a2 + a - 420 = 0 --- > equation 1
Step 1: Factoring the equation1, we get the integer.
a2 + a - 420 = 0
a2 -20a + 21a - 420 = 0
a (a - 20) + 21 (a - 20) = 0
(a -20) (a + 21) = 0
Possibilities of ‘’a’’ value is
a = 20
a = -21
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