the product of 2-digit number is 1998. if the product of their unit digit is 28 and that of tense digit is 15 find the number
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Let the numbers be ab and xy, where a and x are the tenth place digits and b and y are the oneth place digits.
ab * xy = 1998
ax = 15
Only 5 and 3 are single digit numbers that yield the result 15
by = 28
Only 7 and 4 are single digit numbers that yield the result 28.
The units have to 7 and 4 and the tenth place digits are 5 and 3.
so the number is 57 * 34 or 37 *54
Of theise only 37 * 54 = 1998.
Therefore, the two numbers are 37 and 54.
ab * xy = 1998
ax = 15
Only 5 and 3 are single digit numbers that yield the result 15
by = 28
Only 7 and 4 are single digit numbers that yield the result 28.
The units have to 7 and 4 and the tenth place digits are 5 and 3.
so the number is 57 * 34 or 37 *54
Of theise only 37 * 54 = 1998.
Therefore, the two numbers are 37 and 54.
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