The product of 2 number is 400 one of the is 60% larger the order find the sum of number
Answers
Step-by-step explanation:
Given :-
The product of two numbers is 400 one of the is 60% larger the other.
To find :-
Find the sum of numbers ?
Solution :-
Let the other number be X
Then,
One of the numbers = 60% larger than other
=> X+60% of X
=> X+(60% ×X
=> X+(60/100)×X
=> X+(3/5)×X
=> X+(3X/5)
=> (5X+3X)/5
=> 8X/5
Now
The product of the two numbers
=> (8X/5)×X
=> (8X×X)/5
=> 8X²/5
According to the given problem
The product of the two numbers = 400
=> 8X²/5 = 400
=> 8X² = 400×5
=> 8X² = 2000
=> X² = 2000/8
=> X² = 250
=> X = √250
=> X = √(25×10)
=> X = 5√10
The other number = 5√10
One of the numbers = 8X/5
=> (8×5√10)/5
=> 8√10
Now
The sum of the two numbers
=> 8√10+5√10
=> (8+5)√10
=> 13√10
Answer:-
The sum of the two numbers = 13√10
Check:-
The numbers = 8√10 and 5√10
Their product = 8√10 ×5√10
=> 8×5×√(10×10)
=> 40×10
=> 400
Verified the given relations in the given problem.