The product of 2 numbers is 2028. Their HCF is 13. Find the number of such pairs.
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Answer:
Lets 2 numbers be 13a and 13b
Their product is 2028
So, 13a × 13b = 2028
169ab = 2028
ab = 2028/169
ab = 12
Co prime number for 12 are (1,12) and (3,4)
So,th number are (13×1, 13× 12) and ( 13×3, 13×4)
Answer :- (13,156) or (39,52)
Step-by-step explanation:
Their are 2 such pairs.
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