Math, asked by zayedjahangir2010, 16 days ago

The product of 2 numbers is 3380 and their H.C.F. is 13. Determine the L.C.M. of the 2 numbers.

Answers

Answered by singhsahilsanskar
0

Let the two numbers be x and y respectively.

It is given that the product of the two numbers is 2028, therefore,

xy=2028

Also 13 is their HCF, thus both numbers must be divisible by 13.

So, let x=13a and y=13b, then

13a×13b=2028

⇒169ab=2028

⇒ab=

69

2028

⇒ab=12

Therefore, required possible pair of values of x and y which are prime to each other are (1,12) and (3,4).

Thus, the required numbers are (12,156) and (39,52).

Hence, the number of possible pairs is 2.

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