Question

The product of 2 two digit numbers
is 1470. The product of their ones
digits is 10 and the product of their
tens digits is 12. find the two numbers.
plzzz help me with thissss​

Answer 1

Answer:

5*2=10. and 3×4=12 or 6×2=12

Step-by-step explanation:

possible answer are

35×42=1470

hence answer is 35 and 42.

because

45×23=1035

65×22=1430

62×25=1550

Answer 2

The numbers are 35 and 42.

Given

• The product of 2 two-digit numbers is 1470.
• The product of their one's digits is 10.
• the product of their ten's digits is 12.

To Find

The 2 numbers

Solution

Let the two numbers be (10a + b) and (10c + d)

Here, a and c are in 10's place while b and d are in unit's place.

According to the problem,

bd = 10

Now, the possible combination for two numbers to have their product as 10 is-

• 1 X 10
• 2 X 5
• 5 X 2
• 10 X 1

Since b and d are single digits, 10 is not an option

Therefore, if b = 2 or 5, d must be 5 or 2, respectively.

Similarly, ac = 12

Hence the possible combinations are

• 1 X 12
• 2 X 6
• 3 X 4
• 4 X 3
• 6 X 2
• 12 X 1

Here too they cannot take up 12 as a value

Hence, if a = 2, 3, 4, or 6 then c must be 6, 4, 3, or 2 respectively

So possible numbers are

1.  22 and 65
2.  25 and 62
3.  32 and 45
4.  35and 42

According to the problem,

(10a + b)(10c + d) = 1470

Now, 1470 = 2 X 3 X 5 X 7 X 7

Here we can see that:

• 11 is not a factor of 1470, hence 1) is not a possible answer
• 31 is not a factor of 1470, so 2) is not a possible answer.
• 32 is not a factor of 1470, so 3) is not a possible answer.
• Option 4) completely satisfies the criteria, hence the answer is 35 and 42

Hence, the numbers are 35 and 42.

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