Question

the product of 3/4a2(2/3b2+8ab) is​

Answer 1

Answer:

=(

4a2

3

+3b2)4(

3b2

a2−2

)

=( \frac{3}{8a} + 6b) \: \times 2 \times \frac{2a - 2}{3b}=(

8a

3

+6b)×2×

3b

2a−2

= \frac{3 + 48ab}{8a} \times 2 \times \frac{2a - 2}{3b}=

8a

3+48ab

×2×

3b

2a−2

= \frac{3 + 48ab}{8a} \times 2 \times \frac{2a - 1}{3b}=

8a

3+48ab

×2×

3b

2a−1

= \frac{3 + 48ab}{4a} \times \frac{2(a - 1)}{3b}=

4a

3+48ab

×

3b

2(a−1)

= \frac{3(1 + 16ab)}{2a} \times \frac{a - 1}{3b}=

2a

3(1+16ab)

×

3b

a−1

= \frac{(1 + 16ab) \times (a - 1)}{2ab}=

2ab

(1+16ab)×(a−1)

= \frac{a - 1 + 16a {}^{2} b - 16ab}{2ab}=

2ab

a−1+16a

2

b−16ab

Step-by-step explanation:

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Answer 2

Answer:

lol the answer is already given

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