Question

The product of 3 consecutive integers is 120 then the greatest number is​

Answer 1

Given : the product of 3 consecutive integers is 120

To Find : the greatest numbers

Solution:

the product of 3 consecutive integers is 120

Hence 3 consecutive  numbers will be factor of 120

120 = 1 x 120

120 = 2 x 60

120 = 3 x 40

120 = 4 x 30

120 = 5 x 24

120 = 6 x 20

120 = 8 x 15

120 = 10 x 12

So all the factors of 120 are

1 , 2 , 3 , 4 , 5 , 6 , 8 , 10 , 12 , 15 , 20 , 24 , 30 , 40 , 60 , 120

Consecutive factors are:

1 , 2 , 3 , 4 , 5 , 6

1 x 2 x 3 = 6

2 x 3 x 4 = 24

3 x 4 x 5  = 60

4 x 5 x 6 = 120

4 x 5 x 6 = 120

three consecutive integers are 4 , 5 & 6  whose product is 120

and 6 is the greatest number

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