The product of 3 integers is -6000. If two of them are -15 and 10 find the third integer
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Let the three consecutive integers be x,x+1 and x+2.
It is given that the sum of the integers is 24, therefore, we have:
x+(x+1)+(x+2)=24
⇒x+x+1+x+2=24
⇒3x+3=24
⇒3x=24−3
⇒3x=21
⇒x=
3
21
⇒x=7
Therefore, x=7 and the other two integers are:
x+1=7+1=8 and
x+2=7+2=9
Now, we find the product of the integers as shown below:
x(x+1)(x+2)=7×8×9=504
Hence, the product of the integers is 504.
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