Question

the product of 3 integers x,y,z is 192.z=4 and p equals to the average of x and y.what is the minimum possible value of p

Answer 1

Answer:

Step-by-step explanation:

As per the given conditions ;

xyz = 192;

z = 4;

it means xy(4) = 192;

xy = 48;

p = (x+y)/2;

x+y = 2p;

we know that :

There are various combinations to satisfy the condition xy = 48;

like 1*48, 2*24, 3*16, 4*12, 6*8, 10*4.8 ;

out of these combination only 6*8 is satisfy the condition for x+y = 2p for minimum value of p that is 7

Answer 2

Answer:

Minimum value of p = -24.5

Step-by-step explanation:

According to the given conditions:

1)  x*y*z = 192

2)  z=4

3)  p= (x+y)/2

The value of p will be minimum for the minimum value of (x+y)

Substituting the value of z in (1), we get

x*y = 48

so x and y are two numbers whose product is 48.

These numbers can be

1) 1,48 and -1,-48

2) 2,24 and -2,-24

3) 4,12 and -4,-12

4) 6,8 and -6,-8

so minimum value of x+y comes for the value -1,-48 i.e -49

As p= (x+y)/2

so p= -24.5