the product of 4 consecutive natural numbers is 5040 find the numbers
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Answered by
25
Hi ,
Let x , ( x + 1 ) , ( x + 2 ) , ( x + 3 ) are
4 consecutive natural numbers .
Their product = 5040
x( x + 1 ) ( x + 2 )( x + 3 ) = 5040
x( x + 1 )( x + 2 )( x + 3 ) = 70 × 72
x( x + 1 )( x + 2 )( x + 3 ) = 7×8×9×10
x( x+1)(x+2)(x+3) = 7(7+1)(7+2)(7+3)
Therefore ,
Required ,
Four natural numbers are ,
7 , 8 , 9 , 10
I hope this helps you.
: )
Let x , ( x + 1 ) , ( x + 2 ) , ( x + 3 ) are
4 consecutive natural numbers .
Their product = 5040
x( x + 1 ) ( x + 2 )( x + 3 ) = 5040
x( x + 1 )( x + 2 )( x + 3 ) = 70 × 72
x( x + 1 )( x + 2 )( x + 3 ) = 7×8×9×10
x( x+1)(x+2)(x+3) = 7(7+1)(7+2)(7+3)
Therefore ,
Required ,
Four natural numbers are ,
7 , 8 , 9 , 10
I hope this helps you.
: )
Answered by
9
Heya !!!
Let the four consecutive natural Numbers are X , X+1 , X +2 , X+3.
According to question,
Product of Numbers = 5040
X (X+1) (X+2) (X+3) = 5040
X (X+1) (X+2) (X+3) = 7 × 8 × 9 × 10
Here,
X = 7
(X+1) = (7+1) = 8
(X+2) = (7+2) = 9
(X+3) = (7+3) = 10
Hence,
Four consecutive Numbers are 7,8,9 and 10.
HOPE IT WILL HELP YOU....... :-)
Let the four consecutive natural Numbers are X , X+1 , X +2 , X+3.
According to question,
Product of Numbers = 5040
X (X+1) (X+2) (X+3) = 5040
X (X+1) (X+2) (X+3) = 7 × 8 × 9 × 10
Here,
X = 7
(X+1) = (7+1) = 8
(X+2) = (7+2) = 9
(X+3) = (7+3) = 10
Hence,
Four consecutive Numbers are 7,8,9 and 10.
HOPE IT WILL HELP YOU....... :-)
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