Question

The product of 4 consecutive positive integers is 840. Find those numbers.​

Answer 1

Step-by-step explanation:

Let the consecutive numbers be n, (n+1) , (n + 2 ) (n+ 3). then n(n+1)(n + 2 )(n+ 3) = 840. Add and subtarct 1 to the first number of the product. if n = 4 we have 4, 5, 6, 7 n = -7 is not possible -7 does not belongs to the natural number.

Answer 2

Answer:

Step-by-step explanation:

x(x+1)(x+2)(x+3)=840

x(x+1)(x+2)(x+3)=4×5×6×7

x=4