Question

the product of a fraction with the sum of 23/5 and 31/5 is 25 .find the fraction​

Answer 1

Answer:

Let the required fraction be x/y

Therefore, according to the question;

(sum of the given numbers) × (x/y) = 25

23/5 + 31/5 × x/y = 25

54/5 × x/y = 25

x/y = 25×5/54

x/y = 125/54

Thus, 125/54 is the required fraction

Hope it helps...

Answer 2

Answer:

• The fraction is 125/54.

Step-by-step explanation:

Given that:

• The product of a fraction with the sum of 23/5 and 31/5  is 25.

To Find:

• Find the fraction.

Let us assume:

• Let the required fraction be x.

Then,

According to the question,

$\rm{\longmapsto x\times\left(\dfrac{23}{5}+\dfrac{31}{5}\right)=25}$

Adding the numbers,

$\rm{\longmapsto x\times\left(\dfrac{23+31}{5}\right)=25}$

$\rm{\longmapsto x\times\left(\dfrac{54}{5}\right)=25}$

Opening the brackets,

$\rm{\longmapsto x\times\dfrac{54}{5}=25}$

Transposing 54/5 from LHS to RHS and changing its sign,

$\rm{\longmapsto x=25\div\dfrac{54}{5}}$

$\rm{\longmapsto x=25\times\dfrac{5}{54}}$

Multiplying the numbers,

$\rm{\longmapsto x=\dfrac{125}{54}}$

Hence, the required fraction is 125/54.