Question

the product of a number with 18 gives 61 find the number find the number​

Answer 1

Answer:

Let x= ones digit and y=tens digit

According to the question ,

∴ x+ 10y= 6(x+ y)+ 4 ⇒ 10y= 6x+ 6y+ 4− x ⇒ 4y= 5x+ 4

And,from if18is substracted from the number ,the digits are reversed,

∴x+

10y−

18=

y+10x⇒10y−

18=

y+9x⇒9y−

18=

9x

⇒y−

2=

x

Substitute x value into :

4y= 5x+ 4 4y= 5(y− 2)+ 4 4y= 5y− 6 y= 6

Substitute y into :

∴

y−

2=x⇒

6−

2=x⇒

4=

x

∴ The number is 64.

Answer 2

To find : missing number .

Given : product of a number with 18 gives $61$

Solution :  

• Let , $x$ be the missing number .

• As per the given data we know that product of a number with 18 gives $61$
• According to given condition we write as , $18x = 61$
• We take constants at RHS leaving variable at LHS.  
• Simplify the equation using arithmetic operation as required to find the value of $x$.
• Then the result will be the solution for the given linear equation. By using the transposition method.

• $18x = 61$  

          $x =\frac{61}{18}$  

• On simplifying we get , $x =3.38$ .

Hence value of $x$ is $\frac{61}{18}$ or $3.38$ .