Question

The product of a student 4year ago and after 8year later is 28 find the present age of student

Answer 1

$\huge \sf \green{Solution : }$

$\sf \orange{⇒Let , \: the \: Present \: age \: be \: x \: years.}$

$\sf{According \: to \: the \: question,}$

⇒ (x−5) (x+9) = 15

⇒ x² +9x−5x−45−15=0

⇒ x² +4x−60=0

⇒ x² + 10x − 6x − 60 = 0

⇒ x(x+10) − 6(x+10) = 0

⇒ (x+10) (x−6) = 0

⇒ x+10 = 0 and x − 6 = 0

⇒ x = -10 and x = 6

$\sf \green{Hope \: it \: helps \: uh !!}$

Answer 2

⇒ (x−5) (x+9) = 15

⇒ x² +9x−5x−45−15=0

⇒ x² +4x−60=0

⇒ x² + 10x − 6x − 60 = 0

⇒ x(x+10) − 6(x+10) = 0

⇒ (x+10) (x−6) = 0

⇒ x+10 = 0 and x − 6 = 0

⇒ x = -10 and x = 6