The product of additive inverse of x*2-1/2x and x*2-4/3-x is ?
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Given: The term x²-1/2x and x²-4/3-x .
To find: The product of additive inverse of x²-1/2x and x²-4/3-x ?
Solution:
- Now the additive inverse of :
x²-1/2x is 1 - x²/2x
- Here only the additive inverse of first term is considered.
- Multiplying them, we get:
( 1 - x²/2x ) × ( x² - 4 / 3 - x )
(1 - x²)(x² - 4) / 2x(3 - x)
x² - 4 - x^4 + 4x² / 6x - 2x²
- x^4 + 5x² - 4 / 6x - 2x²
x^4 - 5x² + 4 / 2x² - 6
Answer:
So the product is x^4 - 5x² + 4 / 2x² - 6.
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