The product of all integers from 1 to 100 will have the following numbers of zeros at the end?
19
20
22
24
Answers
Answered by
3
Answer:
The correct option is D.
Explanation:
The product of all integers from 1 to 100 is 100!.
The number of trailing zeros in 100! is (100/5)+(100/25) = 24
The formula actually counts the number of factors 5 in n!, but since there are at least as many factors 2, this is equivalent to the number of factors 10, each of which gives one more trailing zero.
Answered by
0
Answer:
Explanation:
The correct option is D.
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