The product of any five consecutive integers is divisible by 120.
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hi your answer is 2,3,4,5,6,hope it helps you
all the above consecutive integers divide 120
all the above consecutive integers divide 120
newcodemaker:
i want to prove it by contradiction
kindly it will be helpful for me if you that
sorry didn't get you
in discrete structures we use contradiction
so i want to do it by contradiction
The product of any five consecutive integers is not divisible by 120.
like this
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Answer:
Yes, the product of any 5 consecutive number is divisible by 120
example 1:
Five consecutive numbers are 2, 3, 4, 5, 6.
Product of consecutive integers is 2 × 3 × 4 × 5 × 6 = 720
( 720 ÷ 120 ) = 6 that means product of consecutive integers is divisible by 120.
Example 2 :
Five consecutive numbers are 10, 11, 12, 13, 14
and the product of these numbers is 240,240
240240 / 120 = 2002
It proves that product of any 5 consecutive numbers is divisible by 120.
Explanation:
general formula of consecutive number is
n, n + 1, n + 2, n + 3, and so on..
They have a difference of 1 between every two numbers.
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