The product of any three consecutive natural number is divisible by
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Answer:
If you have 3 consecutive natural numbers, then at least 1 of them must be divisible by 2, and 1 of them must be divisible by 3. Thus their product must always be divisible by 2x3=6.
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Step-by-step explanation:
Let n,n+1,n+2 be three consecutive natural numbers and P (n) be their product. Then,
P(n)=n(n+1)(n+2)
We have,
P(1)=1×2×3=6, which is divisible by 3 and 6.
P(2)=2×3×4=24, which is divisible by 3, 8 and 6.
P(3)=3×4×5=60, which is divisible by 3 and 6.
P(4)=4×5×6=120, which is divisible by 3, 8 and 6.
Hence, P(n) is divisible by 3 and 6 for all n∈ N.
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