Math, asked by deepaknamala, 1 year ago

the product of digits of numerator in subraction of 12÷5 and 13÷7

Answers

Answered by Adarshthakur11
4
12÷5=12*1/5
=12/5

13÷7=13*1/7
=13/7

subtraction of 12/5 and 13/7
=12/5-13/7
L.C.M of 5 and 7 is 35

therefore
12*7/5*7 - 13*5/7*5
=84/35 - 65/35
=84-65/35
=19/35

numerator=19
product of digits =1*9=9

hope it helps you

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Adarshthakur11: most welcome brother
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