The product of first three terms of a G.P is 1000.If 6 is added to its second term and 7 added to its third term ,the terms become in A.P .Find the G.P
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Let the three numbers be a/r , a, ar.
a/r × a× ar = 1000
a^3 =1000
a = 10
According to the question ,
a/ r ,a+6, ar +7 form an ap
So, 2b = a+ c in an ap
2(a+6)=a/ r + ( ar + 7)
2(10+6)= 10/r + (10r+7)
2(16) = 10/r +10r+7
32–7= 10/r + 10r
25=10/r+ 10r
5= 2/r + 2 r
5r= 2+2r^2
2r^2–5r +2
On factorising the equation we get
r = 1/2 or r= 2
So ,if r= 1/2 ,
The gp is 20, 10,5
If r= 2,
The gp is 5,10,20
I hope it will help uh
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