the product of four consecutive natural number which are multiples of 5 is 15000 find those natural numbers
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Suppose the four consecutive numbers which are multiples of 5 are 5x; 5(x+1); 5(x+2) and 5(x+3)
According to the question the product of these consecutive numbers is 15000, so we have;
5x×5(x+1)×5(x+2)×5(x+3) = 15000⇒625(x+1)(x+2)(x+3) = 15000⇒(x+1)(x+2)(x+3) = 15000625⇒(x+1)(x+2)(x+3) =24Now when x =1, then we have(1+1)(1+2)(1+3) = 2×3×4 = 24
So, x = 1
So four consecutive numbers are;
5×1 = 55(1+1) = 5×2 = 105(1+2) = 5×3 = 155(1+3) = 5×4 = 20
Therefore four consecutive natural numbers are 5, 10, 15 and 20.
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According to the question the product of these consecutive numbers is 15000, so we have;
5x×5(x+1)×5(x+2)×5(x+3) = 15000⇒625(x+1)(x+2)(x+3) = 15000⇒(x+1)(x+2)(x+3) = 15000625⇒(x+1)(x+2)(x+3) =24Now when x =1, then we have(1+1)(1+2)(1+3) = 2×3×4 = 24
So, x = 1
So four consecutive numbers are;
5×1 = 55(1+1) = 5×2 = 105(1+2) = 5×3 = 155(1+3) = 5×4 = 20
Therefore four consecutive natural numbers are 5, 10, 15 and 20.
Hope it's help you
Please mark me in brain list answer
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