Question

) The product of four consecutive natural
numbers is 840. Find the numbers.​

Answer 1

Answer:

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Step-by-step explanation:

Let the consecutive numbers be n, (n+1) , (n + 2 ) (n+ 3).

Given that their product = 840

then n(n+1)(n + 2 )(n+ 3) = 840.

this can also written as n(n+3)⋅(n+1)(n+2) = 840

Add and subtarct 1 to the first number of the product.

[(n²+3n+1)−1][(n²+3n+1)+1] = 840

(n²+3n+1)²−1 = 840

(n²+3n+1)² = 841

(n²+3n+1)² = 29²

(n²+3n+1) = 29

⇒ n²+3n+1–29=0 = n² + 3n - 28

(n + 7) (n - 4) = 0

if n = 4

we have 4, 5, 6, 7

n = -7 is not possible -7 does not belongs to the natural number.

Answer 2

Answer:

4,5,6,7are the numbers