Question

The product of four consecutive positive odd integer is 945.find the number

Answer 1

Answer:

sorry I don't know Bhai

Answer 2

The four consecutive positive odd integers are 3, 5, 7 and 9.

Step-by-step explanation:

Let the four consecutive positive odd integer = x, (x + 2), (x + 4) and (x + 6)

To find, the four consecutive positive odd integer = ?

According to question,

The product of four consecutive positive odd integers = 945

∴ x(x + 2)(x + 4)(x + 6) = 945        ....... (1)

∴ 945 = 3 × 3 × 3 × 5 × 7

= 3 × 5 × 7 × 9

Now, equation (1) becomes,

x(x + 2)(x + 4)(x + 6) = 3 × 5 × 7 × 9

By inspection method, we get

x = 3, x + 2 = 5, x + 4 = 7 and x + 6 = 9

∴ The four consecutive positive odd integers = 3, 5, 7 and 9

Thus, the four consecutive positive odd integers are 3, 5, 7 and 9.