Question

the product of four consecutive positive odd integers is 945. find the numbers.​

Answer 1

Answer:

3,5,7,9

Step-by-step explanation:

x(x+2)(x+4)(x+6)-945=0

(x^2 +10x+24)(x^2+2x)-945=0

x^4 +12x^3 +44x^2 +48x -945=0

(x-3)(x^3 +15x^2 +89x +315)=0

(x-3)(x+9)(x^2 +6x +35)=0

now,because numbers are real and positive

x=3

so,numbers are

3,5,7,9