The product of H.C.F of two numbers and their L.C.M. is 1449. If one of the numbers is 161. Find the other.
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Answer:
1449
Step-by-step explanation:
(a×b) = ( HCF (a ,b) × ( LCM (a,b)) . Here a '= 161 , HCF = w23 and LCM = 1449.
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