Question

The product of Lohith’s age five years ago with his age 9 years later is 15 in years. Find his present age.

Answer 1

Hi! here is your answer.

Let Lohith’s present age be x years.

Age 5 years ago = (x-5)

Age 9 years later hence = (x+9)

Product = (x-5)(x+9) = (x2+9x-5x-45) = (x2+4x-45) =15

(x2+4x-60) = 0

(x2+10x-6x-60) = 0

(x+10)(x-6) = 0

The present age of Lohith is 6 years.

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Answer 2

Step-by-step explanation:

let,

present age of lohith= X

5 years ago= X-5

9 years later= X+9

product= (x-5)*(x+9)=15

=X²+9x-5x-45= 15

=x²+4x= 15+45

=x²+4x= 60

= x²+4x-60= 0

=x²+10x-6x-60=0

= x(x+10)-6(x+10)= 0

= (x+10) (x-6)=0

= x+10=0. (or). x-6=0

= x= -10. (or). x= 6

hence, x value is always in positive terms so x= 6

...... present age of lohith= x= 6