Question

the product of multiplication of number of electrons corresponding to [n+l] =3 & l=2 in Cu

Answer 1

Answer:

the product of multiplication of number of electrons corresponding to [n+l] =3 & l=2 in Cuisines

Answer 2

Concept

An electron could be a charged fundamental particle. It is either free (not attached to any atom), or sure to the nucleus of an atom.

Given

We are providing $(n+l)=3$ and $l=2$ in $Cu.$

Find

We have to search out the product of the multiplication of electrons.

Solution

The electronic configuration of $Cu=1s^22s^22p^63s^23p^64s^13d^10$.

We are on the condition that $(n+l)=3$.

So, there are two cases

When $n=3$ and $l=0$ then it's of configuration $3s$ whose power is $2.$

When $n=2$ and $l=1$ then it's of configuration $2p$ whose power is $6$.

Then the sum of the ability of both cases is $2+6=8$.

We are given $l=2$ then it's of configuration $d$ whose power is $10.$

Thus, a product of multiplication of number of electrons is $8\times 10=80$.

Hence, the product of multiplication of electrons is $80.$

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