Math, asked by nicenamaman7690, 4 months ago

The product of one less than a certain positive number and two less than three times the number is 14. Find the number.

Answers

Answered by gopalpvr
0

Answer:

3

Step-by-step explanation:

let the number = k

according to the problem,

(k-1) (3k-2)=14

3k^2-5k+2-14= 0

3k^2-5k-12= 0

3k^2-9k+4k-12= 0

3k(k-3)+4(k-3)=0

(3k+4)(k-3) = 0

3k+4= 0 or k-3= 0

k = -3/4 or k = 3

k = -3/4 is not a positive number.

so required number= k = 3

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