The product of one less than a certain positive number and two less than three times the number is 14. Find the number.
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Answer:
3
Step-by-step explanation:
let the number = k
according to the problem,
(k-1) (3k-2)=14
3k^2-5k+2-14= 0
3k^2-5k-12= 0
3k^2-9k+4k-12= 0
3k(k-3)+4(k-3)=0
(3k+4)(k-3) = 0
3k+4= 0 or k-3= 0
k = -3/4 or k = 3
k = -3/4 is not a positive number.
so required number= k = 3
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