Question

the product of permeability of free space and permittivity is a) C, b)C-¹, c) C², d)C -²​

Answer 1

Answer:

d) $c^{-2}$

Explanation:

The permeability of free space is denoted by μ

and the permittivity of free space is denoted by ε

The speed of electromagnetic wave in free space is given by

$c=\frac{1}{\sqrt{με} }$

Therefore με=1/$c^{2}$

Or με=$c^{-2}$

Answer 2

Answer:

ans is d)  c^-2

Explanation:

• μξ =(μ÷4π)(ξ4π)=(10^-7)(1÷9×10^9)=1÷(9×10^16)=(3×10^8)^-2=c^-2