Question

The product of place value of two 3s in 253893 is 90,000 9,000 30,000 3,000

Answer 1

The product of the place values of two 3s is 9000.

Step-by-step explanation:

The given number is 253893.

The two 3s are in ones place and in thousands place respectively.

The 3 in ones place has a place value of (3 × 1) = 3 and the 3 in thousands place has a place value of (3 × 1000) = 3000

∴ the product of the place values of two 3s is

= 3 × 3000 = 9000

Note:

For a number abcdef,

the place value of a is 100000a,

the place value of b is 10000b,

the place value of c is 1000c,

the place value of d is 100d,

the place value of e is 10d and

the place value of f is 1f.