Question

The product of Ramu's age (in years) five years ago with his age (in years) 9 years later is 15. Find Ramu's present age.

Answer 1

$\huge{\text{\underline{QUESTION}}}$

The product of Ramu's age (in years) five years ago with his age (in years) 9 years later is 15. Find Ramu's present age.


$\huge{\text{\underline{SOLUTION}}}$

Let Ramu's present age be x years.

Then, His age 5 years ago = ( x - 5 ) years.
His age 9 years ago = ( x + 9 ) years.

_____________________________

$\textsf{\underline{Given }} -$

The product of these ages is 15.

NOW,

$. ^{.} . \: \: (x - 5)(x + 9) = 15 \\ \\ = > {x}^{2} + 9x - 5x - 45 = 15 \\ \\ = > {x}^{2} + 4x - 45 - 15 = 0 \\ \\ = > {x}^{2} + 4x - 60 = 0 \\ \\ = > {x}^{2} + (10 - 6)x - 60 = 0 \\ \\ = > {x}^{2} + 10x - 6x - 60 = 0 \\ \\ = > x(x + 10) - 6(x + 10) = 0 \\ \\ = > (x + 10)(x - 6) = 0$

____________________________


$x + 10 = 0 \\ = > x = - 10$

$x - 6 = 0 \\ = > x = 6$

And we know that x will not be negative

So, x ≠ -10

x = 6

__________________________


Hence, Ramu's present age is 6 years.

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$\huge{\text{\underline{THANKS}}}$

Answer 2

HÉY MÃTÊ HÊRÉ Ìẞ ÛR ÄÑẞ.....
___________________________________


LET RAMU'S age be= x
RAMU'S age before 5 years = x-5
RAMU'S age 9 yrs later = X+9


ÀS, given in the question,
..
(x+9)(x-5)= 15

x2-5x+9x-45=15.

x2+4x-45=15

x2+4x=60.

x2+4x-60=0

x2-6x+10x-60=0

x(x-6)+10(x-6)=0

(X-6=0). \\ (X+10=0)
(X=6). // . (X=-10).......


HÉÑÇĒ THÉ Ïẞ ÑØT ÇÓMÉẞ ÎÑ MÌÑÛẞ(---) ..

ẞØ,Û ÇÁÑ TÄKÉ X=6....


HØP ÏT WÏLL HĒLP ÚH.......