Question

the product of -root 3/5 +root5/2 and root 5 + root 2 is​

Answer 1

Step-by-step explanation:

(-√3/5+√5)(√5+√2)

(-√3/5×√5-√3/5×√2+√5×√5+√5×√2)

(-√3/√5-√6/√5+5+√10)

Taking LCM√5,

(-√3/√5-√6/√5+5√5/√5+√50/√5)

Taking common of 1/√5,

(-√3-√6+5√5+5√5)1/√5

(-√9+10√5)/√5

Here is ur solution...

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