Question

The product of root of √3x²-6x-19√3=0 is​

Answer 1

Answer:

Let me help you for this question....

We know that sum and product of roots of a qudratic equation is

=>  $\alpha + \beta = \frac{-b}{a}$  and   $\alpha \beta = \frac{c}{a}$

=> So, here c = -19$\sqrt{3}$ and a = $\sqrt{3\\}$

=> Product of the roots is = $\frac{-19\sqrt{3} }{\sqrt{3} }$ = -19

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