Math, asked by garvitakalani, 18 days ago

The product of Tanmay’s age five years ago and his age ten years later is 16. Find his present age.​

Answers

Answered by aks4563
1

Answer:

The present age of tanmay is = 6 years

Step-by-step explanation:

Let the present age of tanmay's is = x years

So, 5 years ago tanmay's age was = x-5 years

Ten years after tanmay's age will be = x+10 years

Now by given condition,

(x-5) ×(x+10) = 16

=> x^2 +10x -5x -50 = 16

=> x^2 +5x -50 -16 = 0

=> x^2 +5x -66 = 0

=> x^2 +11x-6x -66 = 0

=> (x+11) ×(x-6) = 0

=> x= -11, 6

Now age cannot be negative,

So, x = 6

So, the present age of tanmay is = 6 years

Answered by Anonymous
1

Answer:

6 year

Step-by-step explanation:

Let tanay's present age be x year

Five yrs ago tanay's age = x-5 year

Ten later tanay's age = x+10 year

According to the question., =(x-5)(x+10)=16

=x² +10x-5x-50=16

=x² +5x-66=0

=x² +11x-6x-66-0

=x (x+11)-6 (x+11)=0

=(x-6)(x+11)=0 =x=6 or x=-11

Since age is positive tanay's present age = 6 year

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