Math, asked by shanvithaaragala, 15 days ago

the product of
 {y }^{2}  \times 2 {y}^{22}  \times 5 {y}^{26}  \: is
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Answers

Answered by hrai86217
1

Answer:

(2−3y−5y

2

) by (2y−1+3y

2

)

= (2−3y−5y

2

)×(2y−1+3y

2

)

= 2(2y−1+3y

2

)−3y(2y−1+3y

2

)−5y

2

(2y−1+3y

2

)

= 4y−2+6y

2

−6y

2

+3y−9y

3

−10y

3

+5y

2

−15y

4

= −15y

4

—19y

3

+5y

2

+7y−2

Answered by Anonymous
2

Answer:

Hi!

Step-by-step explanation:

2−3y−5y 2) by (2y−1+3y 2) = (2−3y−5y 2)×(2y−1+3y 2) = 2(2y−1+3y 2)−3y(2y−1+3y 2)−5y 2(2y−1+3y 2.

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