Math, asked by devsahus6266, 11 months ago

The product of the ages of sachin 8 years ago and 2 years later is 1200 . Find the present age of sachin

Answers

Answered by aggarnav1105
6

Answer:32


Step-by-step explanation:

Let current age be x

(x-2)(x+8) = 1200

x^2 +6x -16 = 1200

x^2= 1216-6x


−6x+1216−x^2=x^2−x^2(Subtract x^2 from both sides)

−x^2−6x+1216=0

Factorize the given equation

(−x+32)(x+38)=0(Factor left side of equation)

−x+32=0 or x+38=0(Set factors equal to 0)

x=32 or x=−38

Check answers. (Plug them in the equation to make sure they work.)

x=32(Works in original equation)

x=−38(Doesn't work in original equation)



Answered by aryanbansi1111
14

Answer:38


Step-by-step explanation:


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