Question

The product of the digit of a two digit no. is 36 if 45 is subtracted from the no. its digits interchanged their places. Find the no.

Answer 1

Let,
The two digit number be 10x+y
A/q,
X×Y = 36 ---------------------->(1)

Now,
10x + y - 45 = 10y + x
=> 10 x + y - 10y - x = 45
=> 9x - 9y = 45
=> 9 ( x - y ) = 45
=> x - y = 45/9
=> x - y = 5
=> x = 5 + y ------------------------->(2)
Put the value of x in the equation (1),
We get,
( 5 + y ) . y = 36
=> y^2 + 5y - 36 = 0
=> y^2 + ( 9 - 4 )y - 36 = 0
=> y^2 + 9y - 4y - 36 = 0
=> y ( y + 9 ) - 4 ( y + 9 ) = 0
=> ( y + 9 ) ( y - 4 ) = 0
So,
y + 9 = 0 or, y - 4 = 0
=> y = - 9 => y = 4

Thus, y = 4
So,
(2) => x = 5+4
=> x = 9
Therefore,
The two digit number is
10×(9)+4
= 90+4
= 94


HOPE IT HELPS YOU......

Answer 2

Hey mate ....
here is your answer...♥♥♥
===================================
Let the two digit number=10x+y

according to the questions. ...
the product of two digit no.is 36

so,x.y=36................. (1)

now ; when we subtract 45from 10x+y its digit no. interchanged...

so;
10x+y-45=10y+x

=》9x-9y=45

=》x-y=5...................... (2)

=》x=5+y

putting the value of x in eq... (1)

(5+y).y=36

=》y^2+5y-36=0

=》y^2+9y-4y-36=0

=》y (y+9)-4 (y+9)=0

=》(y+9)(y-4)=0

=》y+9=0 or y-4=0

y=-9 or4

-9 is not possible so we take only 4

put the value of y in eq.. (2)
x-y=5

=》x=y+5

=》x=9

so the two digit no. is 94......

hope it will help you. ..♥♥♥♥♥♥♥♥♥♥
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