Question

the product of the digits of a two digit number is 24.if its unit's dugit exceeds twice its ten's digit by 2;find the number

Answer 1

This is your answer correct one

Answer 2

Let the digit at one's place be 'y' and that at ten's place be 'x'.

Required number = 10x + y

Given: xy = 24 and y - 2x = 2

Now,

y = 2x + 2

xy = 24

x(2x + 2) = 24

2x ( x + 1 ) = 24

x(x + 1) = 12

x² + x = 12

x² + x - 12 = 0

x² + 4x - 3x - 12 = 0

x(x + 4) - 3(x + 4) = 0

(x + 4)(x - 3) = 0

By zero product rule,

x = - 4 or 3

Since, digits cannot be negative.

x = 3

xy = 24

3y = 24

y = 8

x = 3, y = 8

Required number = 10x + y = 10(3) + 8 = 30 + 8 = 38