The product of the first three numbers in GP with non-fractional common ratio is 216. What are the numbers. If it has 15 terms? What is its sum.
Answers
Answered by
1
Answer:
Let the numbers are ar,aandar.
Then, ar⋅a⋅ar=216
⇒a3=216⇒a=6
Also,
ar(a)+a(ar)+ar(ar)=156
⇒a2(1r+r+1)=156
⇒1+r+r2r=156a2
⇒1+r+r2r=15636
⇒1+r+r2r=133
⇒3+3r+3r2−13r=0
⇒3r2−10r+3=0
⇒3r2−9r−r+3=0
⇒(3r−1)(r−3)=0
⇒r=13orr=3
So, the three numbers are , 2,6and18.
Answered by
24
༼ Answer ༽
let a/r, a, ar are in GP
A/C to question,
(a/r) a ar = 216
a³ = 216
a³ = (6)³
a= 6
again,
sum of their products in pair = 156
(a/r) a + ax ar + arx (a/r) = 156
a²/r+ a²r + a² = 156
36/r+36r+ 36 = 156
36(1/r+r+1) = 156
3(r² +r+ 1) = 13r 3r²+ 3r+ 3-13r = 0
3r²-10r+ 30
3r²-9r-r+ 3 = 0
r = 3 and 1/3
so, numbers are 6/3, 6, 6x3 => 2, 6, 18 numbers are 6x3, 6, 6/3 => 18, 6,2
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