Question

The product of the following reaction : CH2 = CH – CCl3 + HBr
​(a) CH3 – CH(Br) – ​CCl3 (b) CH2(Br) – CH2 – ​CCl3
(c) BrCH2 – CHCl – CHCl2 (d) CH3 – CH2 – CCl3

Answer 1

Answer: The correct answer is (a).

Explanation:

$CH_2=CH-CCl_3 +\overset{HBr}\rightarrow CH_3-CH(Br)-CCl_3$

Given reaction is in the presence of hydrogen bromide which means that addition of proton and bromide ion will take place in accordance with Markovnikov's rule. That is proton from HBr will get bonded to the carbon atom where more number hydrogen atoms are present and bromide ion will get bonded to stable carbo-cation.

Markovnikov's rule states that during addition reaction in alkenes, stable carbo-cation will form and proton will get attached to that carbon  atom which have more number of hydrogen atoms.

Hence,the correct answer is (a).