Math, asked by tanisha49magar10a, 4 months ago

The product of the present ages of Sarita and Gauri is 320. Eight years from now, Sarita's age will
be three times the age of Gauri. What was the age of Sarita when Gauri was born?
a. 48 yrs
b. 32 yrs
c. 40 yrs
d. 36 yrs​

Answers

Answered by nunnabhavanisrini
2

Step-by-step explanation:

S = Sarita’s present age, G = Gauri’s

S*G = 320. G = 320/S

S + 8 = 3(G + 8)

S + 8 = 3(320/S + 8)

=> S = 960 /S + 24 -8 = 960/S + 16

=> S^2 - 16S - 960 = 0

=> S^2 - 16S + 64 -64–960 = 0

=> (S - 8)^2 = 1024

=> S - 8 = sqr 1024 = 32 or -32

=> S = 8 + 32 or 8 - 32 = 40 or - 24

Sarita’s present age is 40

G 320/S = 320/40 = 8

Gauri’s present age is 8

Sarita is 40 - 8 = 32 years old when Gauri was born.

HOPE IT WOULD HELP YOU

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