Question

the product of the roots of the quadratic equation 2x²-13x+k=0 is 7/2. find the value of k​

Answer 1

Step-by-step explanation:

Solution:-

$let \: \alpha \: and \: \beta \: be \: the \: zeros \: of \: the \: the \: polynomial \:$

$(2 {x}^{2} - 13x + k )= 0$

$then \: \alpha \beta = \frac{constant \: term}{coefficient \: of \: {x}^{2} } = \frac{k}{2}$

$but \: \: \alpha \beta = \frac{7}{2} \: \: (given)$

$\frac{k}{2} = \frac{7}{2}$

$k = 7$

hence ,k=7