the product of the roots of the quadratic equation 3 X square + 23 x + K is equal to zero is 20 then kg equal to
Answers
Answered by
2
It is given that -4 is a root of the equation x
2
+px−4=0.
Then, -4 must satisfy the equation,
(−4)
2
+p×(−4)−4=0
16−4p−4=0
4p=12
p=3
Now, the equation x 2
+px+k=0 has equal roots
Therefore,
Discriminant, D=0⟹b
2
−4ac=0
p
2
−4k=0
9−4k=0
k=
4
9
Therefore, p=3 and k=
4
9
.
Answered by
3
Answer:
en, -4 must satisfy the equation,
(−4)
2
+p×(−4)−4=0
16−4p−4=0
4p=12
p=3
Now, the equation x
2
+px+k=0 has equal roots
Therefore,
Discriminant, D=0⟹b
2
−4ac=0
p
2
−4k=0
9−4k=0
k=
4
9
Therefore, p=3 and k=
4
9
.
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