the product of the zeroes of the polynomial aq^2+26q+8 is 18/5. Find the value of a. I am providing 20 points please answer with step by step explanation
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Given Polynomial = aq² + 26q + 8
f(α) = 0
Given Polynomial = aq² + 26q + 8
Comparing with = Ax² + Bx + C
A = a , B = 26 and C = 8
Roots of Polynomial = α and β
Product of Roots = αβ = C / A = 18 / 5
C = 18
A 5
8 = 18
a 5
18a = 40
a = 40 / 18
a = 20 / 9
Hope you got it
@manishthakur100
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