Math, asked by Mrks1, 1 year ago

The product of the zeros of 4u*2+8u is

Answers

Answered by gaurav2013c
0
4u^2 +8u + 0

Here the constant term is not given so we can consider it 0

We know that,

Product of zeroes = constant term / Coficient of u^2

= 0/4

= 0

Mrks1: Thank you so much
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