Math, asked by bishalp191, 1 year ago

The product of the zeros of 4u2+8u2+8u is

Answers

Answered by Bhavyanarula
2
In the given equation,
4u^2+8u^2+8u
=12u^2+8u+0
We know that,
Product of zeros=c/a
=>Product of zeros in the given equation where c=0 and a=12
So,
0/12=0
HOPE it helps
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