The product of the zeros of polynomial
is ???
Anonymous:
Hi
Answers
Answered by
5
Heya !!
P(X) = X³ + 4X+ X - 6
=> X³ + 5X - 6
Product of zeroes = -(Constant term)/Coefficient of X³
Product of zeroes = -(-6) / 1
Product of zeroes = 6.
P(X) = X³ + 4X+ X - 6
=> X³ + 5X - 6
Product of zeroes = -(Constant term)/Coefficient of X³
Product of zeroes = -(-6) / 1
Product of zeroes = 6.
Answered by
4
Hey!!
p ( x ) = x^3 + 4x^2 + x - 6
( It seems to you that you have forget to write 4x^2 )
On comparing ax^3 + bx^2 + cx - d
Product of zeroes = - ( constant term / Coefficients of x^3 )
= - d / a
= - ( - 6 ) / 1
= 6
Hope it will helps you ✌
p ( x ) = x^3 + 4x^2 + x - 6
( It seems to you that you have forget to write 4x^2 )
On comparing ax^3 + bx^2 + cx - d
Product of zeroes = - ( constant term / Coefficients of x^3 )
= - d / a
= - ( - 6 ) / 1
= 6
Hope it will helps you ✌
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