Question

The product of the zeros of
$4 u ^{2} + 8u$

Answer 1

Hi friend!!

Given polynomial is 4u²+8u

we know that product of zeros =

constant term/u²-coefficient

=0/4

=0

Method 2:-

The zeros of the given polynomial are 0, -2.

Their product is 0×(-2)=0.

I hope this will help u ;)