the product of the zeros of the polynomial 4x2+3x+7 is
a)3/4
b)-3/4
c)7/4
d)-7/4
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Given : 4x²+3x-7
To find :product of zeroes of polynomial
Solution:
We have a polynomial:
=4x²+3x- 7
= 4x² +7x - 4x -7 ( factorising)
Taking common:
= x(4x+7)-1(4x+7)
=( x-1)( 4x+7) ( again taking terms common)
Now equating with zero: x-1 =0
x =1
4x+7=0
x= -7/4 (Transposing)
Zeroes of polynomial are 1 and-7/4
Product of zeroes of polynomial is :
= 1×-7/4 ( Multiplying)
we get:
= -7/4
Answer: product of zeroes of polynomial is - 7/4.Option d is correct
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